A solution is 40% acetic acid by mass. The
density of this solution is 1.049 g/mL. Calculate
the mass of pure acetic acid in 460 mL of
this solution at 20 C.
Answer in units of g.
1.049 g/mL x 460 mL x (40/100) = ?
193.0g
To calculate the mass of pure acetic acid in the solution, we need to find the mass of the solution and subtract the mass of the solvent (water).
First, we need to find the mass of the solution. The density of the solution is given as 1.049 g/mL. Therefore, for 460 mL of the solution, the mass of the solution would be:
Mass of solution = Volume of solution * Density of solution
Mass of solution = 460 mL * 1.049 g/mL
Next, we need to find the mass of the solvent (water). Since the solution is 40% acetic acid, it means that the remaining 60% is water. Therefore, we can calculate the mass of the water in the solution:
Mass of water = 0.60 * Mass of solution
Finally, to find the mass of the pure acetic acid, we subtract the mass of the water from the mass of the solution:
Mass of pure acetic acid = Mass of solution - Mass of water
Now, let's calculate the mass of the solution and the mass of the pure acetic acid:
Mass of solution = 460 mL * 1.049 g/mL = 482.54 g
Mass of water = 0.60 * 482.54 g = 289.53 g
Mass of pure acetic acid = 482.54 g - 289.53 g = 193.01 g
Therefore, the mass of pure acetic acid in 460 mL of this solution is approximately 193.01 g.