A salt water swimming pool is 47.0 m long, 25.1m wide, and 2.79 m deep. If the pool is filled with salt water having a density of 1.06 g/ cm3, how many pounds of salt water are in the pool when it is filled?
1 kg = 2.20 lb
I'm not sure how to approach this. I've tried converting the water density into kg, and then to lb, but that doesn't seem right. Any help on where to get started would be appreciated.
I would convert the dimensions of the pool to cm then find the volume of the pool in cm^3.
volume is length x width x depth.
Then mass H2O = volume in cc x density in g/cc.
Convert mass in grams to kg, then convert to lbs.
To find the weight of the salt water in the pool, you need to calculate the volume of the pool first and then multiply it by the density of the salt water.
First, convert the dimensions of the pool from meters to centimeters to match the density in grams per cubic centimeter (g/cm³):
Length = 47.0 m = 4700 cm
Width = 25.1 m = 2510 cm
Depth = 2.79 m = 279 cm
Next, calculate the volume of the pool in cubic centimeters (cm³) using the formula:
Volume = Length x Width x Depth
Substituting the values:
Volume = 4700 cm x 2510 cm x 279 cm
Multiply the resulting volume by the density of the salt water to get the total weight:
Weight = Volume x Density
Substituting the values:
Weight = (4700 cm x 2510 cm x 279 cm) x 1.06 g/cm³
Now, the weight is currently in grams. To convert it to pounds, divide the weight by the conversion factor of 2.20 lb/kg since 1 kg equals 2.20 lb.
Weight in pounds = Weight in grams / (conversion factor)
Substituting the value:
Weight in pounds = (4700 cm x 2510 cm x 279 cm x 1.06 g/cm³) / (2.20 lb/kg)
Calculate this expression to find the number of pounds of salt water in the pool when it is filled.