There are five children in the family. Each child is three years older than the next oldest. The susm of their ages is 65. Whar are the ages fo these children.

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let their ages be

x,x+3,x+6,x+9, and x+12

their sum = 65
5x + 30 = 65
5x = 35
x = 7
so their ages are 7,10,13,16, and 19

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To find the ages of the children, we can follow these steps:

1. Let's assume the age of the youngest child as 'x'. Since each child is three years older than the next oldest, we can express the ages of the children as x, x+3, x+6, x+9, and x+12.

2. The sum of their ages is given as 65. So, we can write an equation:
x + (x+3) + (x+6) + (x+9) + (x+12) = 65

3. Simplify the equation:
5x + 30 = 65

4. Subtract 30 from both sides to isolate the term with 'x':
5x = 35

5. Divide both sides by 5 to solve for 'x':
x = 7

So, the ages of the five children are: 7, 10, 13, 16, and 19.