louise is 4 years younger than jennifer now. In 10 years, louise will be twice the age that jennifer is now.
Please help me set this up.
Set up an Algebraic equation.
Let j=Jennifer j+10= Jennifer's age now
2j+6= Louise age now
2j+6= j+10
-j -j
____________
j+6=10
-6 -6
________
j=4
Louise is 18 years old
Louise is 8 years old now
Nancy is 4 years younger than Monica.Seven years from now the sum of their ages will be 82. How old are they now.
To set up this problem, we can assign variables to the ages of Louise and Jennifer. Let's say the current age of Louise is L, and the current age of Jennifer is J.
The problem states that Louise is 4 years younger than Jennifer now, which can be written as:
L = J - 4
In 10 years, Louise will be twice the age that Jennifer is now. We can represent this as:
L + 10 = 2J
Now we have a system of two equations with two variables:
L = J - 4
L + 10 = 2J
We can solve this system of equations to find the current ages of Louise and Jennifer.