Vertex (3,2)
focus(-3,2)
since you give only one focus, I assume it's a parabola. Since both points lie on the line y=2, the parabola opens horizontally. Recall that
y^2 = 4px
has focus at (p,0) and vertex at (0,0)
Your parabola has obviously been shifted up by 2, so it will be
(y-2)^2 = 4px
Your vertex has been shifted right by 3, so
(y-2)^2 = 4p(x-3)
p is the distance from the vertex to the focus, in this case 6, so we have
(y-2)^2 = 24(x-3)
But since the focus is to the left of the vertex, the parabola opens to the left, and we are left with
(y-2)^2 = -24(x-3)
http://www.wolframalpha.com/input/?i=parabola+(y-2)%5E2+%3D+-24(x-3)