What mass of glucose (c6h12o6)is produced from 18g of co2 when it reacts with water molecule?
6Co2+6H2o→c6h12o6+Co2
for each six moles of CO2, you get one mole of Glucose
moles of CO2: 18/molmassCO2
divide by six
moles of glucose: 3/molmassCO2
grams of glucose: molemassGlucose*moles of glucose
To determine the mass of glucose produced from 18g of CO2, we need to use stoichiometry, which is the relationship between the balanced equation and the molar quantities of the substances involved.
First, let's calculate the number of moles of CO2 in 18g. We can use the molar mass of CO2, which is approximately 44 g/mol.
Number of moles of CO2 = mass of CO2 / molar mass of CO2
Number of moles of CO2 = 18g / 44 g/mol ≈ 0.4091 mol
According to the balanced equation, the ratio between CO2 and glucose is 6:1. This means for every 6 moles of CO2, we have 1 mole of glucose.
Since we have 0.4091 moles of CO2, we can determine the number of moles of glucose produced.
Number of moles of glucose = 0.4091 mol × (1 mol glucose/6 mol CO2) = 0.06818 mol
Now, to find the mass of glucose, we need to multiply the number of moles by the molar mass of glucose (C6H12O6). The molar mass of glucose is approximately 180 g/mol.
Mass of glucose = number of moles of glucose × molar mass of glucose
Mass of glucose = 0.06818 mol × 180 g/mol ≈ 12.3 g
Therefore, approximately 12.3 grams of glucose will be produced from 18 grams of CO2 when it reacts with water.