Deepak👦is twice as old as his brother Vikas👶. If the difference of their ages be 11 years,find their👬present ages.after 18 years ,their👬ages will be twice . Find this also.
d = 2v
d-v = 11
Now just find d and v.
Not sure what you mean by saying that
after 18 years ,their ages will be twice
They can't both be twice as much.
To solve this problem, let's assign variables to each person's age. Let's say Deepak's age is "D" and Vikas's age is "V".
According to the problem, Deepak is twice as old as his brother Vikas, so we can write the equation:
D = 2V ----(Equation 1)
We also know that the difference in their ages is 11 years, so we can write another equation:
D - V = 11 --- (Equation 2)
We can solve this system of equations by substituting Equation 1 into Equation 2:
2V - V = 11
V = 11
Substituting the value of V back into Equation 1, we can find Deepak's age:
D = 2 * 11 = 22
Therefore, presently, Deepak is 22 years old and Vikas is 11 years old.
Now, let's calculate their ages after 18 years. Adding 18 years to their current ages:
Deepak's age after 18 years will be 22 + 18 = 40.
Vikas's age after 18 years will be 11 + 18 = 29.
After 18 years, their ages will be 40 and 29, respectively.