Mona's👧 father👨 is thrice as old as mona👧. After 12 years,his👴age will be twice that of his daughter👩. Find their present ages.
let mona's curent age be y
and father's be x
1st case- 3y=x
2nd case-x+12=2(y+12)
or x+12=2y+24
since x = 3y
3y+12=2y+24
and y = 12
x = 3*12
x = 36
To solve this problem, let's assume Mona's current age is x.
According to the given information, Mona's father is thrice as old as Mona. So, Mona's father's current age would be 3x.
After 12 years, Mona will be x + 12 years old, and her father will be 3x + 12 years old.
According to the second part of the information, Mona's father's age in 12 years will be twice Mona's age in 12 years.
So, we can write the equation:
3x + 12 = 2(x + 12)
Let's solve this equation:
3x + 12 = 2x + 24
Subtracting 2x from both sides:
x + 12 = 24
Subtracting 12 from both sides:
x = 12
Therefore, Mona's current age is 12 years old.
To find her father's age, we plug in the value of x into the equation:
Father's age = 3x = 3 * 12 = 36 years
So, Mona is currently 12 years old, and her father is 36 years old.