Juan has twice as many brothers as sisters. His sister Maria has 5 times as many brothers than sisters. How many children are in the family?
for Julian, the counts could be
brothers 2 sisters 1
brothers 4 sisters 2
Bingo, because then
Maria has 5 brothers and 1 sister
To find the number of children in the family, we need to analyze the information given about Juan and Maria.
Let's start by defining some variables:
Let "x" represent the number of sisters that Juan has.
Since Juan has twice as many brothers as sisters, the number of brothers he has is 2x.
Next, let's find the number of brothers and sisters that Maria has:
Since Maria has 5 times as many brothers as sisters, the number of brothers she has is 5x.
So, the number of sisters she has is x.
Now, let's count the total number of children in the family:
Juan has x sisters and 2x brothers, making a total of (x + 2x) = 3x children.
Maria has x sisters and 5x brothers, making a total of (x + 5x) = 6x children.
Therefore, the total number of children in the family would be the sum of Juan's and Maria's siblings, which is 3x + 6x = 9x children.
Since we don't have any specific value given for x, we cannot determine the exact number of children in the family without additional information.