If the rate law of a chemical reaction is k[NH4+]2[NO2–], what is the order of the reaction?
1. The order of the reaction cannot be determined.
2. 3
3. 1
4. 2
The answer is the second choice, 3. The way you get the order of the reaction is you add the exponents for each of the chemicals. For NH4 its 2 and for NO2 its 1 even though you cant see it. So the answer would be 3 which is the second choice.
If the rate law of a chemical reaction is k[NH4+]2[NO2–], what is the order of the reaction?
1. The order of the reaction cannot be determined.
2. 3
3. 1
4. 2
Well, I guess the reaction is a bit of a "Wild Card" in terms of order. So I'd go with option 1: The order of the reaction cannot be determined. It's like trying to guess the punchline to a joke before you even hear it.
The order of the reaction is determined by the exponents of the reactants in the rate law equation.
In this case, the rate law is k[NH4+]^2[NO2–]. The exponent of [NH4+] is 2, and the exponent of [NO2–] is also 1.
Since the order of a reaction is determined by the sum of the exponents, the order of this reaction is 2+1=3.
Therefore, the correct answer is 2. 3
To determine the order of the reaction, we need to examine the rate law expression and identify the powers to which the reactants are raised.
In this case, the rate law is given as k[NH4+]^2[NO2–].
By looking at the coefficients of NH4+ and NO2– in the rate law, we can determine their respective powers.
The power of NH4+ is 2, while the power of NO2– is also 2.
Therefore, the order of the reaction is 2.
So, the correct answer is option 4: 2.