How many moles of oxygen are produced from the decomposition of 36.7 g of dinitrogen pentoxide?
2N2O5 4NO2 + O2
how many moles N2O5?
You get half that many moles of O2
I don't know. Please help me figure it out!!
To find the number of moles of oxygen produced from the decomposition of dinitrogen pentoxide (N2O5), you need to use the balanced chemical equation.
The balanced equation for the decomposition of dinitrogen pentoxide is:
2N2O5 → 4NO2 + O2
According to the equation, 2 moles of N2O5 produce 1 mole of O2.
First, calculate the molar mass of N2O5:
N2O5 = (2 * atomic mass of N) + (5 * atomic mass of O)
= (2 * 14.01 g/mol) + (5 * 16.00 g/mol)
= 28.02 g/mol + 80.00 g/mol
= 108.02 g/mol
Now you can calculate the number of moles of N2O5:
moles of N2O5 = mass / molar mass
= 36.7 g / 108.02 g/mol
≈ 0.34 mol
According to the balanced equation, 2 moles of N2O5 produce 1 mole of O2. So, you can calculate the number of moles of O2 produced:
moles of O2 = (moles of N2O5) * (1 mole of O2 / 2 moles of N2O5)
= (0.34 mol) * (1 mol / 2 mol)
= 0.17 mol
Therefore, approximately 0.17 moles of oxygen are produced from the decomposition of 36.7 g of dinitrogen pentoxide.
To determine the number of moles of oxygen produced from the decomposition of dinitrogen pentoxide, you need to use stoichiometry and the molar mass of each compound involved.
First, you need to calculate the molar mass of dinitrogen pentoxide (N2O5):
Molar mass of N = 14.01 g/mol
Molar mass of O = 16.00 g/mol
Molar mass of N2O5 = (2 * 14.01) + (5 * 16.00) = 108.02 g/mol
Next, you can calculate the number of moles of N2O5 present in 36.7 g by using its molar mass:
Number of moles = Mass / Molar mass
Number of moles of N2O5 = 36.7 g / 108.02 g/mol
Now, you need to know the stoichiometry of the reaction. From the balanced equation, you can see that 1 mole of N2O5 produces 1 mole of O2. Therefore, the moles of oxygen produced will be equal to the moles of N2O5.
Finally, substitute the calculated moles of N2O5 into the equation:
Number of moles of oxygen = 36.7 g / 108.02 g/mol
Simplifying this expression will give you the number of moles of oxygen produced from the decomposition of 36.7 g of dinitrogen pentoxide.