calculate no of neutrons present in 1*210^25 atoms of oxygen(atomic no of oxygen=8,mass no of oxygen=17
I ASSUME that number is 1.2E25 atoms of oxygen.
There are 9 neutrons in each atom so that will be 1.2E35 x 9 neutrons in that many atoms of O.
To calculate the number of neutrons present in an atom of oxygen, we need to know the atomic number and the mass number of oxygen.
The atomic number of oxygen is 8, which indicates the number of protons in the nucleus of an atom.
The mass number of oxygen is 17, which indicates the total number of protons and neutrons in the nucleus of an atom.
To find the number of neutrons in an oxygen atom, we subtract the atomic number from the mass number:
Number of neutrons = Mass number - Atomic number
In this case:
Number of neutrons = 17 - 8 = 9
Now, we need to calculate the number of neutrons in 1 * 10^25 atoms of oxygen:
Given:
Number of atoms of oxygen = 1 * 10^25
To calculate the number of neutrons, we multiply the number of atoms by the number of neutrons per atom:
Number of neutrons in 1 * 10^25 atoms of oxygen = Number of neutrons per atom * Number of atoms
Number of neutrons per atom = 9 (as calculated earlier)
Number of neutrons in 1 * 10^25 atoms of oxygen = 9 * 1 * 10^25
To multiply a number by 10 raised to the power of another number, you add the exponent to the exponent of 10:
Number of neutrons in 1 * 10^25 atoms of oxygen = 9 * 10^(25+0) = 9 * 10^25
Therefore, the number of neutrons present in 1 * 10^25 atoms of oxygen is 9 * 10^25.