2asquared plus 9a plus 4=0
9
-2 1/5
so cool
2a^2+9a+4=0
2a^2+a+8a+4=0
a(2a+1)+4(2a+1)=0
(2a+1)(a+4)=0
a=-1/2 and a=-4
To solve the quadratic equation 2a^2 + 9a + 4 = 0, we can use the quadratic formula. The formula states that for any quadratic equation in the form ax^2 + bx + c = 0, the solutions (also known as the roots) can be found using the formula:
x = (-b ± √(b^2 - 4ac)) / (2a)
In our case, the equation is 2a^2 + 9a + 4 = 0. Here, a = 2, b = 9, and c = 4.
Substituting these values into the quadratic formula, we have:
a = 2
b = 9
c = 4
a = 2, b = 9, c = 4 into quadratic formula:
x = (-9 ± √(9^2 - 4 * 2 * 4)) / (2 * 2)
x = (-9 ± √(81 - 32)) / 4
x = (-9 ± √49) / 4
x = (-9 ± 7) / 4
From these two possible solutions, we get:
x1 = (-9 + 7) / 4 = -2 / 4 = -0.5
x2 = (-9 - 7) / 4 = -16 / 4 = -4
So the solutions to the equation 2a^2 + 9a + 4 = 0 are a = -0.5 and a = -4.