How many grams of hydrogen chloride acid containing 10% by mass of hydrogen chloride acid would be required to dissolve 13g of zinc
Zn + 2HCl ==> ZnCl2 + H2
mols Zn = grams/atomic mas = ?
Using the coefficients in the balanced equation, convert mols Zn to mols HCl needed. You can see 1 mol Zn uses 2 mol HCl so mols Zn x 2 = mols HCl needed.
Convert mols HCl needed to grams HCl by grams = mols HCl x molar mass HCl. Then since it is only 10% HCl you will need 10x that.
To answer this question, we need to use the concept of stoichiometry and the balanced chemical equation between hydrogen chloride acid (HCl) and zinc (Zn). The balanced equation is:
Zn + 2HCl -> ZnCl2 + H2
From the equation, we can see that 1 mole of zinc reacts with 2 moles of HCl.
Step 1: Convert 13g of zinc to moles.
To do this, we need the molar mass of zinc, which is approximately 65.38 g/mol. Divide the given mass by the molar mass:
13g Zn * (1 mol Zn / 65.38 g Zn) = 0.198 mol Zn
Step 2: Determine the moles of HCl required.
Since the stoichiometry between Zn and HCl is 1:2, we need twice the moles of HCl compared to Zn:
0.198 mol Zn * 2 mol HCl / 1 mol Zn = 0.396 mol HCl
Step 3: Calculate the mass of HCl required.
Now, we need to determine the mass of HCl required. This depends on the concentration of the HCl solution. You mentioned a 10% concentration, which means that 10 g of HCl is present in every 100 g of the solution.
Since we have 0.396 moles of HCl, we can calculate the required mass as follows:
0.396 mol HCl * (10 g HCl / 100 g solution) = 0.0396 g HCl
Therefore, you would need approximately 0.0396 grams of hydrogen chloride acid solution (containing 10% HCl by mass) to dissolve 13 grams of zinc.
It's important to note that the concentration of the HCl solution plays a crucial role in this calculation. Always double-check the given information and its units to make sure your calculation is accurate.