Prepared by disolving 60g CaBr2 280g H2O the final volume of tje solution is 300ml. Calculate the mole of the solution, normality ,weight % of CaBr2,molality ,moles of fraction of CaBr2 ,moles fraction of H2O
You have about 2 days of work here. Tell me what you know how to do, exactly what you don't understand, and post any work you have done toward this problem. I shall be glad to help you through it but I'm not inclined to do all of this work myself.
To calculate various properties of the solution, we need to find the number of moles of CaBr2 and H2O. We can use the given mass and molar mass of each substance to determine the moles.
1. Calculate Moles of CaBr2:
Given mass of CaBr2 = 60g
Molar mass of CaBr2 = (1 x Ca) + (2 x Br) = 40.08 + (2 x 79.90) = 199.88 g/mol
Moles of CaBr2 = Mass / Molar mass = 60g / 199.88 g/mol
2. Calculate Moles of H2O:
Given mass of H2O = 280g
Molar mass of H2O = 2 x (1 x H + 16 x O) = 2 x (1.01 + 16.00) = 18.02 g/mol
Moles of H2O = Mass / Molar mass = 280g / 18.02 g/mol
3. Calculate the mole fraction of CaBr2:
Mole fraction of CaBr2 = Moles of CaBr2 / (Moles of CaBr2 + Moles of H2O)
4. Calculate the mole fraction of H2O:
Mole fraction of H2O = Moles of H2O / (Moles of CaBr2 + Moles of H2O)
5. Calculate the total moles of the solution:
Total moles of the solution = Moles of CaBr2 + Moles of H2O
6. Calculate the normality of the solution:
Normality = (Moles of CaBr2 / Total volume of the solution in L) x 1000
7. Calculate the weight % of CaBr2:
Weight % of CaBr2 = (Mass of CaBr2 / Total mass of the solution) x 100
8. Calculate the molality of the solution:
Molality = Moles of CaBr2 / (Mass of H2O in kg)
To determine the weight fraction, we need the density of the solution, which is not provided in this question.