Maria spent 2/5 of her money on a book and 1/6 of the remainder on a P.E. uniform. If the book costs P105 more than the P.E. uniform, how much money did she have at first?
Starting with x,
2x/5 = b
1/6 (3/5 x) = u
b = u+105
Now just solve for x by substituting in the values of b and u
204
To find out how much money Maria had at first, we can work backward from the given information. Let's start by finding the cost of the P.E. uniform.
Let's assume Maria had x amount of money initially.
She spent 2/5 of her money on a book, leaving her with (1 - 2/5) = 3/5 of her money.
The cost of the P.E. uniform is 1/6 of the remaining money, which is (1/6) * (3/5) = 3/30 = 1/10 of her initial money.
Since the book costs P105 more than the P.E. uniform, the cost of the book is 1/10 of her initial money + P105.
So, (1/10) * x + P105 is the cost of the book.
Since we know that the cost of the book is P105 more than the P.E. uniform, we can set up an equation:
(1/10) * x + P105 = 1/10 * x + P105
Simplifying the equation, we can cancel out 1/10 x from both sides:
P105 = P105
This equation shows that P105 equals P105. However, it does not provide any information about the initial amount of money Maria had.
Therefore, we cannot determine the exact amount of money Maria had at first with the given information.