The weight of a pure sample of KClO3 to be decomposed in order to get 0.96 of O2.
To determine the weight of a pure sample of KClO3 needed to decompose and obtain 0.96 grams of O2, we can use the stoichiometric relationship between KClO3 and O2.
The balanced equation for the decomposition of KClO3 is:
2 KClO3 -> 2 KCl + 3 O2
From the equation, we can see that 2 moles of KClO3 will yield 3 moles of O2. Therefore, we need to calculate the molar mass of KClO3 and use it to determine the required amount.
1. Calculate the molar mass of KClO3:
M(K) = 39.10 g/mol
M(Cl) = 35.45 g/mol
M(O) = 16.00 g/mol
M(KClO3) = M(K) + M(Cl) + 3 * M(O)
= 39.10 + 35.45 + 3 * 16.00
= 39.10 + 35.45 + 48.00
= 122.55 g/mol
2. Determine the amount in moles of O2:
Amount of O2 = 0.96 g / M(O2)
= 0.96 g / 32.00 g/mol (molar mass of O2)
= 0.03 mol O2
3. Calculate the amount of KClO3 needed:
Since the molar ratio is 2:3 between KClO3 and O2,
Amount of KClO3 = (0.03 mol O2 / 3 mol O2) * 2 mol KClO3
= 0.02 mol KClO3
4. Convert moles to grams:
Weight of KClO3 = Amount of KClO3 * M(KClO3)
= 0.02 mol * 122.55 g/mol
= 2.45 g
Therefore, the weight of the pure sample of KClO3 needed to decompose in order to obtain 0.96 grams of O2 is approximately 2.45 grams.
To determine the weight of a pure sample of KClO3 necessary to obtain 0.96 grams of O2, you need to calculate the molar ratio between KClO3 and O2, and use it to scale the weight.
Step 1: Find the molar mass of KClO3
The molar mass of KClO3 can be calculated by summing the atomic masses of potassium (K), chlorine (Cl), and three oxygen atoms (O).
Molar mass of KClO3 = (atomic mass of K) + (atomic mass of Cl) + (3 x atomic mass of O)
Step 2: Determine the molar ratio between KClO3 and O2
The balanced chemical equation for the decomposition of KClO3 is:
2 KClO3 → 2 KCl + 3 O2
From the equation, we can see that two moles of KClO3 produce three moles of O2. Therefore, the molar ratio between KClO3 and O2 is 2:3.
Step 3: Calculate the number of moles of O2
To determine the moles of O2 required, divide the mass of O2 by its molar mass:
moles of O2 = mass of O2 / molar mass of O2
Step 4: Use the molar ratio to calculate the moles of KClO3
Since the molar ratio between KClO3 and O2 is 2:3, the number of moles of KClO3 can be calculated using the following equation:
moles of KClO3 = (moles of O2 / 3) * 2
Step 5: Calculate the weight of KClO3
To determine the weight of KClO3 needed, multiply the number of moles of KClO3 by its molar mass:
weight of KClO3 = moles of KClO3 * molar mass of KClO3
By following these steps, you should be able to determine the weight of a pure sample of KClO3 required to obtain 0.96 grams of O2.
well, if you get X moles of O2, you decomposed 3x/2 moles of KClO3
.96/32-3/2*massKClO3/molmassKClO3
solve for massKClO3