At a pressure 48 kPa, the gas in a cylinder has a volume of 15 liters. Assuming temperature remains the same, if the volume of the gas is decreased to 8 liters, what is the new pressure?
PV=k
so,
P*8 = 48*15
To find the new pressure of the gas when the volume is decreased to 8 liters, we can use Boyle's Law, which states that the pressure and volume of a gas are inversely proportional at constant temperature.
Boyle's Law equation:
P1 * V1 = P2 * V2
Where:
P1 = Initial pressure
V1 = Initial volume
P2 = New pressure (to be found)
V2 = New volume
Given information:
P1 = 48 kPa
V1 = 15 liters
V2 = 8 liters
Let's substitute the values into the equation and solve for P2:
P1 * V1 = P2 * V2
48 kPa * 15 liters = P2 * 8 liters
To isolate P2, divide both sides of the equation by V2:
P2 = (48 kPa * 15 liters) / 8 liters
Now we can calculate the new pressure:
P2 = (48 kPa * 15 liters) / 8 liters
P2 = 720 kPa / 8 liters
P2 = 90 kPa
Therefore, the new pressure of the gas when the volume is decreased to 8 liters is 90 kPa.