find the equation of the line that is tangent to the curve 𝙛(𝑥)= 5 +3x² -x⁵ at the point (1,7)

1 answer

slope = f' = 6 x - 5 x^4

at x = 1
slope = m = 6(1)-5(1)^4
so
m = 1
y = 1 x + b
to get b
7 = 1(1) + b
b = 6
so
y = x + 6

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