Moss and Roy both decide to go out for a 2 course dinner. Moss' meal cost twice as much as Roy's meal, however Roy spent $3 more than Moss for his dessert. Moss spent $11 on his desert. The bill came to $75. How much did Roy spend for his meal and dessert?

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roy dessert costs 14$

To solve this problem, let's set up some equations based on the given information.

Let's say the cost of Roy's meal is x. Then the cost of Moss' meal is twice that, which is 2x.

We also know that Roy spent $3 more than Moss for his dessert. So, Roy's dessert cost Moss' dessert plus $3, which is 11 + 3 = $14.

The total cost of Roy's meal and dessert is x + $14.

The total cost of Moss' meal and dessert is 2x + $11.

Finally, we know that the bill came to $75. So, we can set up the equation:

(x + $14) + (2x + $11) = $75

Now we can solve for x:

x + $14 + 2x + $11 = $75
3x + $25 = $75
3x = $75 - $25
3x = $50
x = $50 / 3
x = $16.67 (rounded to two decimal places)

Therefore, Roy spent $16.67 on his meal and dessert.