Moss and Roy both decide to go out for a 2 course dinner. Moss' meal cost twice as much as Roy's meal, however Roy spent $3 more than Moss for his dessert. Moss spent $11 on his desert. The bill came to $75. How much did Roy spend for his meal and dessert?
To figure out how much Roy spent for his meal and dessert, we can break down the information given in the problem.
Let's assume the cost of Roy's meal is 'x' dollars. Moss' meal cost twice as much, so we can say Moss' meal cost '2x' dollars.
We're also told that Roy spent $3 more than Moss for his dessert, and Moss spent $11 on his dessert. So, the cost of Roy's dessert would be $11 - $3 = $8.
To find the total bill, we need to add up the cost of Roy's meal, Moss' meal, Roy's dessert, and Moss' dessert. Since the bill came to $75, we can write the equation as:
x + 2x + 8 + 11 = 75
Combining like terms:
3x + 19 = 75
Subtracting 19 from both sides:
3x = 56
Dividing both sides by 3:
x = 56 / 3
Calculating x:
x ≈ 18.67
Therefore, Roy spent approximately $18.67 for his meal. To find out how much Roy spent for his meal and dessert, we need to add the cost of his meal and dessert:
$18.67 + $8 = $26.67 (rounded to two decimal places)
Hence, Roy spent approximately $26.67 for his meal and dessert.