Ticket rate for the science exibition is 10rs for a child and 26 rupees for an adult. 740 rupees was got from 50person. How many children among them?
No of children = 50-x
No of adult = x
10x + 26[50-x] = 740
= 10x + 1300 - 26x = 740
10x - 26x + 1300 = 740
-16x + 1300 = 740
16x = 1300 - 740 = 560
16x = 560
x = 560/16 = 35
x = 35
No of children = 35
10 c + 26 a = 740
but a = 50 - c
so
10 c + 26 (50 - c) = 740
-16 c + 1300 = 740
16 c = 560
c = 35
No of children = 50-x
No of adult = x
10x + 26[50-x] = 740
= 10x + 1300 - 26x = 740
10x - 26x + 1300 = 740
-16x + 1300 = 740
16x = 1300 - 740 = 560
16x = 560
x = 560/16 = 35
x = 35
No of children = 35
Nice 😊 but 2022 elle
35 children
To solve this problem, we can use a system of linear equations. Let's assume 'c' represents the number of children and 'a' represents the number of adults.
Given:
The ticket rate for a child is 10 rupees.
The ticket rate for an adult is 26 rupees.
A total of 740 rupees was collected from 50 people.
We need to find out the number of children among them. We can set up two equations based on the given information.
Equation 1: c + a = 50 (since there were a total of 50 people)
Equation 2: 10c + 26a = 740 (the total amount collected)
Now, we can solve this system of equations to find the values of 'c' and 'a'.
One method to solve this is substitution:
From Equation 1, we can express c in terms of a:
c = 50 - a
Substituting this value of c into Equation 2:
10(50 - a) + 26a = 740
500 - 10a + 26a = 740
16a = 240
a = 15
Substituting this value of 'a' back into Equation 1:
c + 15 = 50
c = 50 - 15
c = 35
Therefore, there are 35 children among the 50 people.