2a) Simplify the expressions for A and B, where A=x+4/xsquared+9x+20 and B= 3xsquared-9x/xsquared+3x-18

b) Are the two expressions equivalent? Justify your answer.
c) Determine
i) A-B
ii) A•B
iii) B÷A

you probably meant:

A= (x+4)/(xsquared+9x+20)
= (x+4)/((x+4)(x+5))
= 1/(x+5) , x ≠ -4

B = (3xsquared-9x)/(xsquared+3x-18)
= 3x(x - 3)/((x+6)(x-3))
= 3x/(x+6) , x ≠ 3

clearly they are not equivalent

I am sure you can handle the algebra from this point.

To simplify the expressions for A and B, we need to factorize the given expressions as much as possible and then cancel out any common factors.

a) Simplifying expression A:

We have A = (x + 4) / (x^2 + 9x + 20)

First, we try to factorize the denominator (x^2 + 9x + 20):

We can rewrite the expression as (x + 4)(x + 5).

So, A becomes: A = (x + 4) / [(x + 4)(x + 5)]

Now, we can cancel out the common factor of (x + 4) in the numerator and denominator:

A = 1 / (x + 5)

Therefore, the simplified expression for A is A = 1 / (x + 5).

Similarly, let's simplify expression B:

We have B = (3x^2 - 9x) / (x^2 + 3x - 18)

First, we factorize the denominator (x^2 + 3x - 18):

We can rewrite the expression as (x + 6)(x - 3).

So, B becomes: B = (3x^2 - 9x) / [(x + 6)(x - 3)]

Now, we can cancel out the common factor of 3x in the numerator and denominator:

B = (x - 3) / (x + 6)

Therefore, the simplified expression for B is B = (x - 3) / (x + 6).

b) To determine if the two expressions A and B are equivalent, we need to compare them.

From the simplifications above, we have:
A = 1 / (x + 5)
B = (x - 3) / (x + 6)

The expressions A and B are not equivalent because their numerators and denominators are different.

c) Now, let's calculate the following:

i) A - B:

A - B = (1 / (x + 5)) - ((x - 3) / (x + 6))

To subtract fractions, we need to find a common denominator, which is (x + 5)(x + 6):

A - B = [(1 * (x + 6)) - ((x - 3) * (x + 5))] / [(x + 5)(x + 6)]

Expanding and simplifying, we get:

A - B = (x + 6 - (x^2 + 2x - 15)) / [(x + 5)(x + 6)]

Simplifying the numerator:

A - B = (-x^2 + 3x - 9) / [(x + 5)(x + 6)]

Therefore, A - B = (-x^2 + 3x - 9) / [(x + 5)(x + 6)].

ii) A • B:

A • B = [(x + 4) / (x + 5)] * [(x - 3) / (x + 6)]

To multiply fractions, we can multiply the numerators and denominators directly:

A • B = [(x + 4)(x - 3)] / [(x + 5)(x + 6)]

Expanding, we get:

A • B = (x^2 + x - 12) / [(x + 5)(x + 6)]

Therefore, A • B = (x^2 + x - 12) / [(x + 5)(x + 6)].

iii) B ÷ A:

B ÷ A = [(x - 3) / (x + 6)] ÷ [1 / (x + 5)]

To divide fractions, we can multiply the first fraction by the reciprocal of the second:

B ÷ A = [(x - 3) / (x + 6)] * [(x + 5) / 1]

Simplifying:

B ÷ A = (x - 3)(x + 5) / (x + 6)

Therefore, B ÷ A = (x - 3)(x + 5) / (x + 6).