Quentin is lifting a 10 kg dumbbell by pulling upward on it with a 108.1 N force. What is the acceleration of the dumbbell as a result of this force?
1.01 m/s
To find the acceleration of the dumbbell, we can use Newton's Second Law of Motion, which states that the acceleration of an object is directly proportional to the net force applied to it and inversely proportional to its mass.
The formula for Newton's Second Law of Motion is:
F = m * a
Where:
F = Net force (108.1 N)
m = Mass of the dumbbell (10 kg)
a = Acceleration
Rearranging the formula to solve for acceleration, we have:
a = F / m
Plugging in the given values:
a = 108.1 N / 10 kg
Calculating the result:
a ≈ 10.81 m/s²
Therefore, the acceleration of the dumbbell as a result of the 108.1 N force is approximately 10.81 m/s².
To determine the acceleration of the dumbbell, we can use Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force applied to it and inversely proportional to its mass. The formula for this is:
acceleration (a) = net force (F) / mass (m)
Given that the force applied by Quentin is 108.1 N and the mass of the dumbbell is 10 kg, we can substitute these values into the equation to find the acceleration:
a = 108.1 N / 10 kg
a = 10.81 m/s^2
Therefore, the acceleration of the dumbbell, as a result of the force applied by Quentin, is 10.81 m/s^2.
a = f / m
a = [108.1 - (10 * g)] / 10