Calculus

Calculate the interval of convergence.
Sigma from n=1 to infinity of (n!*x^n)/n^n.

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asked by andre
  1. try using the ratio test. You should be able to show that the series converges for |x| < e

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    posted by Steve
  2. I tried and I got
    |x|lim n-infinity of |(n/n+1)^n|
    which I get |x|<1

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    posted by andre

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