a bullet is fired with velocity 55m/sec at a target.if if the sound of collision heard after 7second.find the distance between target and gun.(speed of sound in air=330m/sec
7 seconds?
Call the time, which I think is a typo, T
distance is d
t1 = time out
t2 = time back
t1 + t2 = T
t1 = d/55
t2 = d/330
so
d/55 + d/330 = T
d = T /(1/55 + 1/330)
If the distance is x meters, then since time = distance/speed,
x/55 + x/330 = 7
x = 330m
Now, the problem is that the bullet will drop 176m in the 6 seconds spent in the air.
So, now we have to include the angle of the trajectory, which complicates matters some.
To find the distance between the target and the gun, we can use the formula:
Distance = Speed x Time.
Given that the speed of sound in air is 330 m/sec and the time taken for the sound of collision to be heard is 7 seconds, we can substitute these values into the formula:
Distance = 330 m/sec x 7 sec = 2310 meters.
Therefore, the distance between the target and the gun is 2310 meters.