General Chemistry

what is the value of Kc if PbCl(s)=1.5g, [Pb2+]=1.6*10^-2 M and [Cl-] =3.2*10^-2 M at equilibrium? (The molar mass of PbCl(s) is 278 g/mol and its density is 5.85g/cm^3.)

asked by Anonymous
  1. Kc=[Pb2+]*[2*Cl-]^2

    Kc=1.6E-2 * 4*(3.2E-2)^2

    posted by bobpursley

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