If the concentration of I^-1 is found to be 2.4 x 10^-3 mol/L in a saturated solution of PbI2. What is the Ksp of PbI2?
........PbI2 ==> Pb^2+ + 2I^-
I.......solid....0.......0
C.......solid....x.......2x
E.......solid....x.......2x
Ksp = (Pb^2+)(I^-)^2
Ksp = (x)(2x)^2
You know x = 2.4E-3 M, substitute and solve for Ksp.