Sodium azide fully decomposes at 300 degrees celcius at a volume of 3,5 cubic decometer,calculate the mass of sodium azide pellets used

To calculate the mass of sodium azide pellets used, we need to know the molar mass of sodium azide (NaN3).

The molar mass of sodium (Na) is 22.99 g/mol, and the molar mass of nitrogen (N) is 14.01 g/mol. Since there are three nitrogen atoms in sodium azide, the molar mass of sodium azide is:

(22.99 g/mol) + (3 * 14.01 g/mol) = 65.99 g/mol

Now, let's calculate the number of moles of sodium azide using the ideal gas law equation:

PV = nRT

Where:
P = pressure (assumed to be constant)
V = volume of gas (3.5 cubic decameters = 3,500 L)
n = number of moles of sodium azide
R = ideal gas constant (0.0821 L·atm/mol·K)
T = temperature (300 degrees Celsius = 573 Kelvin)

Rearranging the equation to solve for the number of moles (n), we have:

n = PV / RT

Substituting the known values:

n = (P * V) / (R * T)
n = (1 atm * 3,500 L) / (0.0821 L·atm/mol·K * 573 K)
n ≈ 67.75 mol

Finally, we can calculate the mass of sodium azide pellets used:

Mass = moles * molar mass
Mass = 67.75 mol * 65.99 g/mol
Mass ≈ 4,471.22 g

Therefore, approximately 4,471.22 grams of sodium azide pellets were used.