Math

5k^2u^2 3z^2
________ + ____
12b^2d^2 4bk^3

How would I solve this?

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asked by Nadine
  1. (5k^2)(u^2)(3z^2)+ 12(b^2)(d^2)(4bk^3)
    = 15(k^2)(u^2)(z^2) + 48(b^3)(d^2)(k^3)

    then factor:

    3(k^2) [5(u^2)(z^2) + 16(b^3)(d^2)k

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    posted by HK

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