physics

a body is projected horizontally from height of 78.4 m with a velocity 10 m/s . its velocity after 3 sec

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  1. u = 10 m/s forever
    v = -gt = -9.81 (3) = - 29.4 m/s

    check if it hit the ground
    d = (1/2) g t^2 = 4.9 * 9 = 44.1 so still in the air

    speed = sqrt (10^2 + 29.4^2)

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    posted by Damon
  2. First, check that it hasn't yet hit the ground.

    Finding it has not, then get the resultant of the horizontal and vertical velocities
    √(10^2 + (9.8*3)^2)
    at an angle of 71° below the horizontal

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    posted by Steve

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