a bullet is fired horizontally with a velocity of 200m/s.if the acceleration due to gravity is 10m/s-2, un first second through which height it will move.
To determine the height through which the bullet will move in the first second, we need to consider the kinematic equations of motion.
1. The horizontal velocity of the bullet remains constant at 200 m/s throughout its motion.
2. The vertical motion of the bullet is influenced by the acceleration due to gravity, which is directed downward.
In the first second, the bullet's vertical motion can be analyzed using the equation:
h = ut + (1/2)gt^2
Where:
h = height (vertical displacement)
u = initial vertical velocity (0 m/s since the bullet is fired horizontally)
g = acceleration due to gravity (-10 m/s^2, negative since it acts downward)
t = time (1 second)
Plugging in the values into the equation, we have:
h = 0(1) + (1/2)(-10)(1^2)
h = 0 + (-5)
h = -5 meters
The negative sign indicates that the bullet moves downward due to gravity. Therefore, in the first second, the bullet would have moved 5 meters downward.
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un first second through which height it will move
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