Maths

If X=loga(n), y=logc(n) where nis not equal to one . Prove that x-y/x+y=logb(c)-logb(a)/logb(c)+logb(a)

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asked by Joel
  1. 1/x = logn(a)
    1/y = logn(c)

    (x-y)/(x+y) = (1/y - 1/x)/(1/y + 1/x)
    = logn(c/a)/logn(c*a)

    logb(c)-logb(a) = logb(c/a)
    logb(c)+logb(a) = logb(c*a)

    The two ratios are equal.

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    posted by Steve

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