A weight suspended from an ideal spring oscillates up and down with a period T. If the amplitude of the oscillation is doubled, the period will be ?

A. 1.5 T
B. 2T
C. T/2
D. T
E. 4T

the same

2T

1.5T

To understand how the period changes when the amplitude of the oscillation is doubled, we need to first understand the relationship between period and amplitude in an ideal spring system.

In an ideal spring system, the period (T) of the oscillation is the time it takes for one complete cycle. The period is determined by the mass of the weight (m) and the stiffness of the spring (k), following the equation T = 2π√(m/k).

When the amplitude of the oscillation doubles, it means that the weight now moves twice as far from the equilibrium position compared to before. Doubling the amplitude does not affect the mass or the spring constant, so we need to determine how it affects the period.

The period of an oscillation is independent of the amplitude. This means that the period of oscillation will remain the same regardless of the amplitude of the oscillation. So, the correct answer is D. T

0.5T