Math

For a certain day,the depth of water,h, in metres in PEI, in hours is given by the formula:h(t) = 7.8 + sin3.5 (pi/6(t-3)), t E [0,24], assume t=0 represents midnight. Provide an algebraic solution to determine the time(s) of day, the water reaches the depth of 10.29 m( give your answer in hours and minutes)

asked by ba
  1. Stacey/ba, please don't switch names

    7.8 + sin3.5 (pi/6(t-3)) = 10.29
    sin3.5 (pi/6(t-3)) = 2.49
    not possible, sin(?) cannot be > 1

    when you first posted this, you had
    3.5sin (pi/6(t-3))

    I will change it to

    7.8 + 3.5sin (pi/6(t-3)) = 10.29
    3.5sin (pi/6(t-3)) = 2.49
    sin (pi/6(t-3)) = .71142..
    (pi/6(t-3)) = .79152 or (pi/6(t-3)) = π - .79152 = 2.35..

    if (π/6)(t-3) = .79152..
    t-3 = 1.5117..
    t = 4.5117..

    find the other value of t, using the second part of above

    posted by Reiny
  2. Lol sorry but that's what I got 4.51 I just wasn't sure how to get the second value

    posted by ba
  3. could you please help in finding the second value of t. thank you

    posted by angelina

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