The solution of x for equation
a (bx - c) = d - (x + e)
(a > 0 and b > 0)
the answer is x = ac + d - e/ab + 1
How?
abx-ac=d-x-e
ab=-1
which immediately poses a problem, because either a or b is negative, which is <0, and the problem stated both were >0
a(bx-c) = d-(x+e)
abx-ac=d-x-e
(ab+1)x = ac+d-e
x = (ac+d-e)/(ab+1)
To solve the equation a(bx - c) = d - (x + e), you can follow these steps:
Step 1: Distribute and simplify on both sides of the equation:
a(bx - c) = d - (x + e)
abx - ac = d - x - e
Step 2: Group like terms:
abx + x = d - ac - e
Step 3: Combine x terms on the left side:
(ab + 1)x = d - ac - e
Step 4: Divide both sides by (ab + 1) to solve for x:
x = (d - ac - e)/(ab + 1)
Thus, the solution for x in terms of a, b, c, d, and e is x = (d - ac - e)/(ab + 1).
Note: It's important to note that the solution assumes certain conditions, such as a > 0 and b > 0. Make sure to consider the limitations and constraints provided in the question when applying this solution.