For a certain day,the depth of water,h, in metres in PEI, in hours is given by the formula:h(t) = 7.8sin (pi/6(t-3)), t E [0,24], assume t=0 represents midnight. Provide an algebraic solution to determine the time(s) of day, the water reaches the depth of 10.29 m( give your answer in hours and minutes)
7.8sin (pi/6(t-3)) = 10.29
sin (pi/6(t-3)) = 1.319 <--- ??
I suspect that you have left out a term in the definition of h(t). Fix it and then proceed with the solution.posted by Steve
Sorry it's h(t)=7.8+3.5sin((pi/6(t-3))posted by Stacy