physics

A skier traveling at 26.2 m/s encounters a 23 degree slope.
(a)If you could ignore friction, to the nearest meter, how far up the hill does he go?
(b)If the coefficient of kinetic friction in the previous problem was actually 0.11 and the slope 30 degrees, to the nearest meter how far up the hill does he go?

  1. 👍
  2. 👎
  3. 👁
  1. Vo = 26.2 m/s[23o].
    Yo = 26.2*sin23 = 10.2 m/s.

    a. Y^2 = Yo^2 + 2g*h = 0.
    10.2^2 - 19.6h = 0, 19.6h = 104.8, h = 5.3 m.

    d*sin23 = 5.3, d = 13.7 m. up hill.

    1. 👍
    2. 👎

Respond to this Question

First Name

Your Response

Similar Questions

  1. Physics

    A skier is pulled up a slope at a constant velocity by a tow bar. The slope is inclined at 23.0° with respect to the horizontal. The force applied to the skier by the tow bar is parallel to the slope. The skier's mass is 55.3 kg,

  2. COLLEGE PHYSICS

    A 62.0 kg skier is moving at 6.50 m/s on a frictionless, horizontal snow covered plateau when she encounters a rough patch 3.50 m long. The coefficient of kinetic friction between this patch and returning to friction-free snow,

  3. Physic

    A 61-kg skier, coasting down a hill that is an angle of 23 to the horizontal, experiences a force of kinetic friction of magnitude 72N. The skier's speed is 3.5m/s near the top of the slope. Determine the speed after the skier has

  4. physics

    A skier traveling 11.0 m/s reaches the foot of a steady upward 19.6° incline and glides 13.8 m up along this slope before coming to rest. What was the average coefficient of friction?

  1. Physics

    A 50kg skier starts from rest from the top of a 100m slope. What is the speed of the skier on reaching the bottom of the slope? Neglect friction. would i do this: =PE + KE =mgh +1/2mv^2 =50(10)(100) + 1/2 (50)v^2 =50000 +25v^2

  2. Physics

    Starting from rest, a skier slides 100 m down a 28 degree slope.How much longer does the run take if the coefficient of kinetic friction is 0.17 instead of 0?

  3. physics

    An Olympic skier moving at 20.0 m/s down a 30.0 degree slope encounters a region of wet snow and slides 145 m before coming to a halt. What is the coefficient of friction between the skis and the snow?

  4. physics 2..help PLEASE!!

    A 63 kg skier encounters a dip in the snow's surface that has a circular cross section with a radius of curvature of 12 m. If the skier's speed at point A in Figure 8-25 is 7.9 m/s, what is the normal force exerted by the snow on

  1. Physics

    A skier stands on a 5 degree slope . if the coefficient of static friction is 0.1, does the skier start to slide?

  2. Physics

    An Olympic skier moving at 19 m/s down a 26 degree slope encounters a region of wet snow and slides 136 m before coming to a halt. What is the coefficient of friction between the skis and the snow? ( g = 9.81 m/s2)

  3. physics

    A skier starts from rest at the top of a frictionless incline of height 20.0 m, as shown in the figure. At the bottom of the incline, the skier encounters a horizontal surface where the coefficient of kinetic friction between skis

  4. Physics

    A skier traveling 12.0 m/s reaches the foot of a steady upward 18° incline and glides 18.2 m up along this slope before coming to rest. What was the average coefficient of friction?

You can view more similar questions or ask a new question.