Question: A Toyota car travelled at the rate of 70 km/hour leaves the house 2 hours after a Kia car has left and overtakes it in 5 hours. at what rate was Kia car travelling?
What's the Formula pls?
Thanks
distance travellrd by toyota is 70 into 5 = 350 km
but kia car travelled 5+2 hrs
so 350/7=50kmph
To solve this problem, we can use the formula: Speed = Distance/Time.
Let's assume that the Kia car was traveling at a speed of x km/h.
Given that the Toyota car traveled at a rate of 70 km/h, and it took 5 hours for the Toyota car to overtake the Kia car.
The Kia car left 2 hours before the Toyota car, so the Kia car traveled for 5 + 2 = 7 hours.
Now, let's find the distance traveled by both cars:
Distance traveled by the Kia car = Speed * Time = x * 7 km
Distance traveled by the Toyota car = Speed * Time = 70 * 5 km
Since both cars travel the same distance when the Toyota car overtakes the Kia car, we can set up the equation:
x * 7 = 70 * 5
Now, let's solve for x:
x = (70 * 5) / 7
x = 50 km/h
Therefore, the Kia car was traveling at a rate of 50 km/h.
To find out the rate at which the Kia car was traveling, you can use the formula:
Rate = Distance / Time
In this problem, we are given the time it took for the Toyota car to overtake the Kia car, which is 5 hours. We also know that the Toyota car left the house 2 hours after the Kia car. Therefore, the Kia car had a head start of 2 hours.
Now, let's calculate the distance traveled by each car:
For the Toyota car:
Distance = Rate * Time
Distance = 70 km/h * (5 + 2) hours (since it traveled for 5 hours plus the 2-hour head start it had)
Distance = 70 km/h * 7 hours
Distance = 490 km
Now that we know the distance traveled by the Toyota car, we can use the same formula to find the rate at which the Kia car was traveling:
Rate = Distance / Time
Rate = 490 km / 5 hours
Rate = 98 km/h
So, the Kia car was traveling at a rate of 98 km/h.