In an interbarangay basketball league the team from barangay Culiat has won 12 out of 25 games a winning percentage of 48% .We have seen that they need to win 8 games consecutively to raise their percentage to at least 60%. What will be their winning percentage if they win 10 games in a row?? Please show the solution
To find out the winning percentage, we need to divide the number of wins by the total number of games played and then multiply by 100.
Let's start with the given information: The team from barangay Culiat has won 12 out of 25 games, which represents a winning percentage of 48%.
To calculate their winning percentage, we use the following formula:
Winning Percentage = (Number of Wins / Total Number of Games) * 100
So, for the initial percentage:
Winning Percentage = (12 / 25) * 100
= 0.48 * 100
= 48%
Now, let's calculate the number of wins needed to reach a winning percentage of at least 60%.
We know that the team needs to win 8 consecutive games to raise their percentage to at least 60%. Since they have already won 12 games, they need to win an additional 8 games.
Total Number of Wins = 12 + 8
= 20
Now, let's calculate the new winning percentage if they win 10 games in a row:
Total Number of Games Played = 25 + 10
= 35
Winning Percentage = (Number of Wins / Total Number of Games) * 100
= (20 / 35) * 100
≈ 57.14%
Therefore, if the team from barangay Culiat wins 10 games in a row, their winning percentage will be approximately 57.14% (rounded to two decimal places).
percentage = (12 + 10)/(25 + 10)
= 22/35
= .6285..
or appr 62.9 %
8 is the answer
12+8/25+8 = .6060
.6060 times 100
=60.60