Solubility (g/100gH2O)

Substance 20∘C 50∘C
KCl 34.0 42.6
NaNO3 88.0 114.0
C12H22O11 (sugar) 203.9 260.4

Using the above table, determine whether each of the following solutions will be saturated or unsaturated at 50 ∘C.

1.) Adding 19.7 g KCl to 35.0 g H2O

2.)Adding 184 g NaNO3 to 75.0 g H2O

3.)Adding 87.8 g sugar to 25.0 g H2O

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  1. For KCl at 50 C.
    42.6 g KCl x (35.0g H2O/100 g H2O) = 14.9 which means 14.9 g KCl can be dissolved in 35.0 g H2O. That means it will be saturated since 19.7 g KCl is greater than what will dissolve.
    2 and 3 are done the same way.

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