math

9x+3y-4z=35
x+y-z=4
2x-5y-4z+48=0

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asked by unni
  1. I assume you are trying to solve this system.

    9x+3y-4z=35 **
    x+y-z=4 ***
    2x-5y-4z = -48 ****

    subtract **** from **
    7x + 8y = 83 ##
    4 times *** ----> 4x + 4y - 4z = 16
    subtract **** from the above
    2x + 9y = 64 ###

    7 times ### ---> 14x + 63y = 448
    2 times ## ----> 14x + 16y = 166
    subtract those last two
    47y = 282
    y = 6

    sub that into ## to get x

    Now you have x and y,
    sub that into *** to get z

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    posted by Reiny

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