An object is located midway between the focal point and the center of a concave spherical mirror. Draw a ray diagram to locate its image. Is the image real or virtual, erect or inverted, magnified or reduced in size?
Completely baffled by above question and the next question. I've gotten the answers completely wrong to both, but would like to understand what is correct.
An object is located three times the focal length from a concave spherical mirror. Draw a ray diagram to locate its image. Is the image real or virtual, erect or inverted, magnified or reduced in size?
Thank you
http://hyperphysics.phy-astr.gsu.edu/hbase/geoopt/imggo/raymir.gif
https://encrypted-tbn1.gstatic.com/images?q=tbn:ANd9GcT4fTOd46EYralXaqhpkJSx0faUxgY8YFlDr3nwVeO4aQ8oxj4f
So for the 1st question, I answered Virtual, Erect, and Magnified. It is marked wrong.
The 2nd question, I finally got Real, Inverted, and Reduced and it is marked correct.
Still don't understand what to do about the first question.
Thanks for trying to help me.
https://www.google.com/imgres?imgurl=https%3A%2F%2Fi.ytimg.com%2Fvi%2FlVBymD0TyaM%2Fhqdefault.jpg&imgrefurl=https%3A%2F%2Fwww.youtube.com%2Fwatch%3Fv%3DlVBymD0TyaM&docid=uu8WzLsazrTYjM&tbnid=ap9UiYUSNX-PeM%3A&w=480&h=360&bih=368&biw=720&ved=0ahUKEwj-gJamr_nNAhVE9IMKHXULDzIQMwgoKAUwBQ&iact=mrc&uact=8
so I see it as real, inverted, and larger, Note on this sketch count as the object the downward arrow between f and c
Sure, let me explain how to solve both questions.
For the first question, you need to follow these steps:
1. Draw a horizontal line to represent the principal axis of the mirror.
2. Mark the center of the mirror on the principal axis.
3. Draw a vertical line through the center of the mirror, perpendicular to the principal axis. This line is called the optical axis.
4. Mark the focal point on the optical axis, which is half the distance between the center of the mirror and the focal point.
5. Place the object on the principal axis, exactly at the midpoint between the focal point and the center of the mirror.
6. Draw two incident rays from the object: one parallel to the principal axis, and another passing directly through the focal point.
7. Now, draw the reflected rays from the mirror. The ray parallel to the principal axis will pass through the focal point after reflection, and the ray passing through the focal point will become parallel to the principal axis after reflection.
8. Extend the reflected rays beyond the mirror.
9. The point where the reflected rays intersect is the location of the image.
For the first question, the image formed will be real, inverted, and diminished in size compared to the object.
Let's move on to the second question:
1. Follow the same steps as before to draw the mirror, principal axis, and focal point.
2. Place the object on the principal axis at a location three times the focal length from the mirror.
3. Draw two incident rays: one parallel to the principal axis and another passing directly through the focal point.
4. Draw the reflected rays from the mirror.
5. Extend the reflected rays beyond the mirror to find the point of intersection.
6. Analyze the location of the image to determine its properties.
For the second question, the image formed will be real, inverted, and smaller in size compared to the object.
Remember that concave mirrors have different image characteristics depending on the position of the object relative to the mirror. The location of the object relative to the focal point affects whether the image is real or virtual, inverted or erect, and magnified or reduced in size.
I hope this explanation helps you understand the process and the correct answers to both questions. Feel free to ask if you have any further questions!