What volume of 0.10 M NaOH can be prepared from 250. mL of 0.30 M NaOH?
A) 0.075 L
B) 0.25 L
C) 0.75 L
D) 0.083 L
E) 750 L
To calculate the volume of 0.10 M NaOH that can be prepared from 250 mL of 0.30 M NaOH, we can use the formula:
M1V1 = M2V2
Where:
M1 = initial concentration
V1 = initial volume
M2 = final concentration
V2 = final volume
First, let's plug in the given values:
M1 = 0.30 M
V1 = 250 mL
M2 = 0.10 M
We need to solve for V2, so
V2 = (M1V1) / M2
Substituting the values:
V2 = (0.30 M * 250 mL) / 0.10 M
V2 = 75 L
Therefore, the volume of 0.10 M NaOH that can be prepared from 250 mL of 0.30 M NaOH is 75 L.
The correct answer is option A) 0.075 L.
To calculate the volume of 0.10 M NaOH that can be prepared from 250 mL of 0.30 M NaOH, you can use the formula:
M1 * V1 = M2 * V2
where:
M1 = initial molarity
V1 = initial volume
M2 = final molarity
V2 = final volume
Let's plug in the values we have:
M1 = 0.30 M
V1 = 250 mL
M2 = 0.10 M
V2 = ?
Rearranging the formula to solve for V2, we have:
V2 = (M1 * V1) / M2
Substituting the values:
V2 = (0.30 M * 250 mL) / 0.10 M
V2 = 75 mL
Now, we need to convert the volume from milliliters to liters by dividing by 1000:
V2 = 75 mL / 1000 mL/L
V2 = 0.075 L
Therefore, the volume of 0.10 M NaOH that can be prepared from 250 mL of 0.30 M NaOH is 0.075 L.
So, the correct answer is A) 0.075 L.
mL1 x M1 = mL2 x M2
250 mL x 0.30M = mL2 x 0.10