a sports car can accelerate fo 0 to 60 in 3.2seconds what is the acceleration of the car in m/s^2 what distance would it travel at this time
26.8 m/s = 60 mph
You do not say but I assume you mean 60 mph or 26.8 m/s
v = a t
26.8 = a (3.2)
a = 26.8/3.2
d = (1/2) a t^2
= .5 (a) (3.2)^2
To calculate the acceleration of the car in m/s², you need to know the final velocity (v) and the time (t) taken to reach that velocity. The final velocity in this case is from 0 to 60 mph (which is approximately 26.8 m/s). The time taken to reach that velocity is given as 3.2 seconds.
First, convert the final velocity from mph to m/s:
26.8 m/s.
Next, plug the values into the formula for acceleration:
acceleration (a) = (final velocity - initial velocity) / time
Since the initial velocity is 0, the formula becomes:
acceleration (a) = final velocity / time
acceleration (a) = 26.8 m/s / 3.2 s
acceleration (a) ≈ 8.375 m/s²
So, the acceleration of the car is approximately 8.375 m/s².
To calculate the distance traveled during this time, you can use the formula:
distance = initial velocity × time + 0.5 × acceleration × time²
Since the initial velocity is 0, the formula simplifies to:
distance = 0.5 × acceleration × time²
distance = 0.5 × 8.375 m/s² × (3.2 s)²
distance ≈ 13.504 meters
Therefore, the distance the car would travel in 3.2 seconds is approximately 13.504 meters.