When an object is droped from a certain height , it's distance from the starting point varies as the square of the time it has been falling . If a body falls through 288m in 6 seconds then what is the distance covered by the object in the tenth second?
that will be
h(10)-h(9)
So Is the distance covered by the object in the tenth second 152 ?
That's what I get.
To solve this problem, we can use the equation for distance covered by a falling object as a function of time, which states that the distance covered is proportional to the square of the time:
Distance = constant * time^2
We are given that the object falls through 288m in 6 seconds. We can use this information to find the value of the constant:
288 = constant * (6)^2
288 = constant * 36
constant = 288 / 36
constant = 8
Now that we have the constant, we can find the distance covered by the object in the tenth second:
Distance = constant * time^2
Distance = 8 * (10)^2
Distance = 8 * 100
Distance = 800m
Therefore, the distance covered by the object in the tenth second is 800 meters.