Math

The expenses of orphanage are party constant and partly vary as the number of the boys in the orphanage. The expenses were Rs. 10,000 for 150 boys and Rs. 8,400 for 120 boys . Find the expenses for 330 boys.

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  1. your equation takes the form

    cost = nx + b, where x is the number of boys, n is the cost per boy and b is the constant

    given: (150,10000) and (120,8400)
    cost per boy = (10000 - 8400)/(150-120)
    = 160/3
    (notice this is just like finding the "slope" )

    so
    Cost = (160/3)x + b
    use of the cases, (150,10000)
    10000 = (160/3)(150) + b
    b = 2000

    cost = (160/3)x + 2000
    when x = 330
    cost = (160/3)(330) + 2000 = 19600

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  2. Thankyou :D

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  3. Thankyou

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  4. Why are you switching names ?

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  5. No not switching names that's my friend Sarvesh. We both study together

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  6. Can u please answer one more question of his?

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