Find the slope of the line whose parametric equations are x=2-t and y=1=2t
fi this line passes through (2,y) find the value of y
compute also the value of t
t = 2-x, so
y = 1+2(2-x) = 5-2x
At t=0, we have (2,1)
To find the slope of the line with parametric equations x = 2 - t and y = 1 + 2t, we can compare the coefficients of t in both equations. The slope of the line is given by the ratio of the coefficient of t in the y equation to the coefficient of t in the x equation.
In this case, the coefficient of t in the y equation is 2, and the coefficient of t in the x equation is -1. Therefore, the slope of the line is 2 / -1 = -2.
Now, if the line passes through the point (2, y), we can substitute x = 2 and y = y into the parametric equations to find the value of t and y.
From x = 2 - t, substitute x = 2 to get:
2 = 2 - t
t = 0
From y = 1 + 2t, substitute t = 0 to get:
y = 1 + 2(0)
y = 1
Therefore, the value of y when the line passes through (2, y) is 1. The value of t is 0.