Emmanuel wants to tile his rectangular floor. one of which is larger than the other.
a)what area will be covered by the "8x8"tile? "16x16" tile?
It would help if you proofread your questions before you posted them.
What are the dimensions of the floors?
The 8x8 tile covers 64 square units (inches, cm?)
Same with 16x16.
To find out what area will be covered by each tile size, we need to first determine the dimensions of the rectangular floor and then calculate the area of the tiles.
Let's assume the dimensions of Emmanuel's rectangular floor are given as length (L) and width (W). We are also given that one of the tiles is 8x8 and the other tile is 16x16.
To find the area covered by the 8x8 tile, we multiply the length by the width of the tile:
Area covered by 8x8 tile = 8 x 8 = 64 square units.
Similarly, to find the area covered by the 16x16 tile, we multiply the length by the width of the tile:
Area covered by 16x16 tile = 16 x 16 = 256 square units.
So, the area covered by the 8x8 tile is 64 square units, while the area covered by the 16x16 tile is 256 square units.
Remember, the actual coverage area of the tiles may be slightly less due to grout lines or variations in installation, but this calculation assumes a perfect fit.