what number whose sum of its digit is 26 becomes 6000 when rounded to the nearest thousand.
well, we know that the number is between
5500 and 6500
There must be many possibilities:
5579
5588
5597
...
6497
6488
6497
To find the answer, we need to follow these steps:
1. Let's assume the number we are looking for has three digits (to become 6000 when rounded to the nearest thousand).
2. We know that the sum of its digits is 26.
3. Now, let's say the hundreds digit is "x", the tens digit is "y", and the units digit is "z".
4. Based on step 2, we can write the equation: x + y + z = 26.
5. Since the number needs to be rounded to the nearest thousand, the hundreds digit should be 6.
6. So we have x = 6, and the equation is now: 6 + y + z = 26.
7. We can rearrange the equation to find: y + z = 26 - 6 = 20.
8. To satisfy this equation, the sum of the tens and units digit should be 20.
9. We also need to consider that the units digit cannot be 0 (because this would make the number two digits instead of three).
10. We can go through the possible combinations of y and z to find the combination that adds up to 20.
- If y = 0, then z = 20.
- If y = 1, then z = 19.
- If y = 2, then z = 18.
- If y = 3, then z = 17.
- If y = 4, then z = 16.
- If y = 5, then z = 15.
- If y = 6, then z = 14.
- If y = 7, then z = 13.
- If y = 8, then z = 12.
- If y = 9, then z = 11.
11. We can exclude the cases where y = 0, 1, 2, 3, 4, 5, 6, 7, 8 because that would make the units digit 0, making it a two-digit number.
12. The only possible combination left is y = 9 and z = 11.
13. Therefore, the number we are looking for is 6911, where the sum of its digits is 26, and when rounded to the nearest thousand, it becomes 6000.